Hi Aida,
It's a little difficult to understand all the details of your use
case. However these are the recommendations:
1. When the first of this image is shown, the input image
disappears: It seems that you have some processor output observer working.
This is the default behavior of the output observer
2. When the first of these images is shown, the previous image
doesn't appear in view1 and appears in view0: It seems that in some part of
the code, the first image is hidden in the view1. This could be again the
default behavior of the processor observer.
I hope this could give you some hints on finding the problem.
Otherwise I would like to ask you if you could provide me more details about
your use case.
Best regards,
Xavi
From: Aida Ninyerola [mailto:[email protected]]
Sent: miércoles, 09 de mayo de 2012 13:27
To: Xavier Planes
Cc: [email protected]
Subject: Re: [Gimias-developers] configurating an standard working area
hi again,
i've almost all my images in the view that i want except thow of them
my process begins opening an image that it's going to be an input and it is
shown in view0 as the working area hasn't changed
then we change to the new working area that has the two views
later there are 8 more images which are shown correctly in view 0, but when
the first of this image is shown, the input image dissapears (it has not the
check in the data tree)
we continue loading a new image that is created during the process and it is
correctly shown in view1
after this, 8 new images are shown in view 1, but as before, when the first
of these images is shown, the previous image doesn't appear in view1 and
appears in view0
if i later make GetRenderingTree( )->Show(m_Processor->GetOutputDataEntity(
8 ),true); it appears but i think that's not the solution
i've tried to follow the process but i can't get to the point that makes
this cange
i know it's a little mess, so ask me whatever you need
thanks,
aida
--- Begin Message ---
hi again,
i've almost all my images in the view that i want except thow of them
my process begins opening an image that it's going to be an input and it is
shown in view0 as the working area hasn't changed
then we change to the new working area that has the two views
later there are 8 more images which are shown correctly in view 0, but when
the first of this image is shown, the input image dissapears (it has not the
check in the data tree)
we continue loading a new image that is created during the process and it is
correctly shown in view1
after this, 8 new images are shown in view 1, but as before, when the first
of these images is shown, the previous image doesn't appear in view1 and
appears in view0
if i later make GetRenderingTree( )->Show(m_Processor->GetOutputDataEntity(
8 ),true); it appears but i think that's not the solution
i've tried to follow the process but i can't get to the point that makes
this cange
i know it's a little mess, so ask me whatever you need
thanks,
aida
2012/5/9 Aida Ninyerola <[email protected]>
great, I didn't understand correctly this variable.
now it works all perfectly
thanks again!
aida
2012/5/9 Xavier Planes <[email protected]>
Hi Aida,
The variable “num” is the output number of the processor that has
been modified. It’s not related to any view. You need to decide in what view
you want to show the image and write the appropriate code in the function
OnModifiedOutput(), depending on the output that has been modified.
For example, you can decide that the output image number 0 will be
shown in the view 0 and the output image number 1 will be shown in the view
1.
Best regards,
Xavi
From: Aida Ninyerola [mailto:[email protected]]
Sent: miércoles, 09 de mayo de 2012 9:29
To: Xavier Planes
Cc: [email protected]
Subject: Re: [Gimias-developers] configurating an standard working area
Hi,
Thank you for the explanation. It was very clear.
But still have another question. When is this variable num defined with the
view where I want to show the image? I can't find when is the
OnModifiedOutput function called.
Is in the OnInit function where I define each image in which view is going
to be shown?
Thanks for all your help!
Aida
--- End Message ---
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