I completely new to GIMP, so I apologise in advance for what might seem to be
obvoius to an advanced user.
I am trying to open a JPEG from MS Access using VB script. I have looked at many
examples of similar scripting on this site, but all are far too complex for me
to follow (I'm a newbie - remember! - thanks).
Examples such as "Gimp -s --a ("file name)" or [filename] or just filename just
leave me confused.. Or examples with [filename], similarly. Do I use square
brackets? Etc.
The advice I am looking for is simple:
I need to call the Gimp program followed by the path to the file to be opened.
The command line I have is:
"C:\program files\gimp 2\bin\GIMP 2.6 " b:\vehpics\123456.jpg
Do I need additional command line parameters? Are the brackets correct?
A similar command line opens up the correct file in mspaint - which I would
rather not use.
Any help will be appreciated.
Wadey
--
Wadey (via www.gimpusers.com/forums)
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