See my answer in context
On 7/29/15 8:10 AM, Konstantin Khomoutov wrote:
On Wed, 29 Jul 2015 07:48:10 -0700
Ying Huang <huangyi...@gmail.com> wrote:
Hi,
great thanks for your attention,
Yes, git log --oneline --format %H --follow -- hello.txt is
better than using awk.
git log --oneline --format %H --follow -- hello.txt \
| while read name; do
git difftool "$name" "$name^1"
done
Unfortunately, if you observe carefully, you will soon find that
*_it skipped some commits_*. I strongly doubt the fault is the ^ git
operator.
My solution is using an array to save the output first: see my
script bellow:
I'm afraid I don't "get" your problem statement.
As I understood it, you told that,
1) say, let the history of hello.txt includes 3 commits, and
2) you'd like to see three diff views -- one for each of
those commits, and
3) each such diff view should display the changes between
the indicated commit and its parent commit.
Is that correct?
Yes, I want to see all 3 of them, each one diff against its parent.
Say, we have these 3 commits, just for easy:
commit1
commit2
commit3
I am expecting the following diff running:
git difftool commit1^! "$1"
git difftool commit2^! "$1"
git difftool commit3^! "$1"
While, only these two are running:
git difftool commit1^! "$1"
git difftool commit3^! "$1"
commit2 is not run. That's my problem, and I don't know why......
If yes, then if a commit has a name (its sha-1 hash sum) <rev>,
then the name of its first (or sole) parent commit is <rev>^1,
and the way to get a difference between them is by passing these
two arguments to a difftool.
Just in case (to remove the possibility of a certain common
misunderstanding), a diff view is always generated between a pair
of commits ignoring any commits which might naturally form a chain
between those commits in that pair.
Sure, I understand this.
--
Best Regards,
Ying
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