Felipe Contreras wrote:
>> Looking at this closely once again.
>> You've already hit the beginning. What are you continuing? Take the
>> example of a compound expression with @{-
>
> Yeah, we could break, but I would prefer the break to happen naturally
> when in the for loop check.
This is followed by a condition on upstream_mark: just change that
from if/else if/ and there's a break; at the end anyway.
The continue is misleading and should be removed.
>> On another note, I think you've fixed a bug: @{-1}{0} was parsing to
>> the same value as @{-1}@{0} before your patch.
>
> Yeap.
Write a note about it in the commit message atleast? I found it to be
a very non-trivial conclusion.
>>> + if (interpret_nth_prior_checkout(str, &buf) > 0) {
>>> + detached = (buf.len == 40 && !get_sha1_hex(buf.buf,
>>> sha1));
>>> + strbuf_release(&buf);
>>> + if (detached)
>>> + return 0;
>>
>> Neat. I'd set reflog_len to zero and made sure that the last part of
>> the function wouldn't be executed. How did you get away without
>> setting refs_found to 1 though?
>
> The rest of the code is not executed, there's no need if @{-N}
> evaluates to a SHA-1. There's no ref to dwim, and there's no reflog
> anyway. We just fetch the SHA-1 and return.
Obviously the return 0 breaks out of the function. I meant what
happens if it's not detached. I'll answer it myself: you have a
string that's either not 40-characters, or doesn't resolve to a valid
object. You haven't found anything yet. Now, you'll be going down
the reflog_len codepath and calling dwim_log() to set the refs_found.
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