Ronnie Sahlberg wrote:

> --- a/builtin/tag.c
> +++ b/builtin/tag.c
> @@ -701,11 +702,12 @@ int cmd_tag(int argc, const char **argv, const char 
> *prefix)
>       if (annotate)
>               create_tag(object, tag, &buf, &opt, prev, object);
> -     lock = lock_any_ref_for_update(ref.buf, prev, 0, NULL);
> -     if (!lock)
> -             die(_("%s: cannot lock the ref"), ref.buf);
> -     if (write_ref_sha1(lock, object, NULL) < 0)
> -             die(_("%s: cannot update the ref"), ref.buf);
> +     transaction = ref_transaction_begin();
> +     if (!transaction ||
> +         ref_transaction_update(transaction, ref.buf, object, prev,
> +                                0, !is_null_sha1(prev)) ||
> +         ref_transaction_commit(transaction, NULL, &err))
> +             die(_("%s: cannot update the ref: %s"), ref.buf, err.buf);

Makes sense for the _update and _commit case.  (BTW, why is have_old
a separate boolean instead of a bit in flags?)

For the _begin() case, can ref_transaction_begin() ever fail?  xcalloc
die()s on allocation failure.  So I think it's fine to assume
transaction is non-null (i.e., drop the !transaction condition), or if
you want to be defensive, then label it as a bug --- e.g.:

        if (!transaction)
                die("BUG: ref_transaction_begin() returned NULL?");

Otherwise if ref_transaction_begin regresses in the future and this
case is tripped then the message would be

        fatal: refs/tags/v1.0: cannot update the ref:

which is not as obvious an indicator that the user should contact
the mailing list.

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