Hi Junio,
On Thu, 9 Oct 2014, Junio C Hamano wrote:
> I didn't mean multiple uses of ?= for the same variable. I meant
> multiple uses of (references to) the variable. I.e. wouldn't FOO and
> BAR behave differently below?
>
> FOO := $(shell random)
> BAR = $(shell random)
> all::
> echo $(FOO) and $(BAR)
> echo twice $(FOO) and $(BAR)
You're correct, of course, my mistake. I just tested with this:
R ?= $(shell echo $$RANDOM)
all:
echo The values of $(R), $(R) and $(R)
and of course a "make" yields three different numbers. Sorry for missing
that.
So what we should do is something like
ifeq ($(uname_S),)
uname_S := $(shell uname -s)
endif
even if repeating that pattern is kind of ugly...
Thanks for correcting my mistake,
Dscho
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