Karthik Nayak <[email protected]> writes:
> +void strbuf_utf8_align(struct strbuf *buf, align_type position, unsigned int
> width,
> + const char *s)
> +{
> + int display_len = utf8_strnwidth(s, strlen(s), 0);
> + int utf8_compenstation = strlen(s) - display_len;
compensation, perhaps? But notice you are running two strlen and
then also a call to utf8-strnwidth here already, and then
> + if (!strlen(s))
> + return;
you return here without doing anything.
Worse yet, this logic looks very strange. If you give it a width of
8 because you want to align like-item on each record at that column,
a record with 1-display-column item will be shown in 8-display-column
with 7 SP padding (either at the beginning, or at the end, or on
both ends to center). If it happens to be an empty string, the entire
8-display-column disappears.
Is that really what you meant to do? The logic does not make much
sense to me, even though the code may implement that logic correctly
and clearly.
> + if (display_len >= width) {
> + strbuf_addstr(buf, s);
> + return;
> + }
Mental note: this function values the information more than
presentation; it refuses to truncate (to lose information) and
instead accepts jaggy output. OK.
> + if (position == ALIGN_LEFT)
> + strbuf_addf(buf, "%-*s", width + utf8_compenstation, s);
> + else if (position == ALIGN_MIDDLE) {
> + int left = (width - display_len)/2;
> + strbuf_addf(buf, "%*s%-*s", left, "", width - left +
> utf8_compenstation, s);
> + } else if (position == ALIGN_RIGHT)
> + strbuf_addf(buf, "%*s", width + utf8_compenstation, s);
> +}
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