On Tue, Mar 01, 2016 at 03:36:26PM -0800, Junio C Hamano wrote:
> This will be necessary when we start reading from a split bundle
> where the header and the thin-pack data live in different files.
>
> The in-core bundle header will read from a file that has the header,
> and will record the path to that file. We would find the name of
> the file that hosts the thin-pack data from the header, and we would
> take that name as relative to the file we read the header from.
Neat. I'm hoping this means you're working on split bundles. :)
> diff --git a/builtin/bundle.c b/builtin/bundle.c
> index 4883a43..e63388d 100644
> --- a/builtin/bundle.c
> +++ b/builtin/bundle.c
> @@ -36,8 +36,9 @@ int cmd_bundle(int argc, const char **argv, const char
> *prefix)
> }
>
> memset(&header, 0, sizeof(header));
> - if (strcmp(cmd, "create") && (bundle_fd =
> - read_bundle_header(bundle_file, &header)) < 0)
> + header.bundle_file = bundle_file;
What are the memory ownership rules for header.bundle_file?
Here you assign from either an argv parameter or a stack buffer, and
here...
> @@ -112,6 +111,8 @@ void release_bundle_header(struct bundle_header *header)
> for (i = 0; i < header->references.nr; i++)
> free(header->references.list[i].name);
> free(header->references.list);
> +
> + free((void *)header->bundle_file);
> }
You free it.
The call in get_refs_from_bundle does do an xstrdup().
Should we have:
void init_bundle_header(struct bundle_header *header, const char *file)
{
memset(header, 0, sizeof(*header));
header.bundle_file = xstrdup(file);
}
to abstract the whole procedure?
-Peff
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