@linvinus so if a name is in a word list the style that sets overrides the
style from the function call syntax? You should make that very clear in the
submission to Scintilla.
In the case where the type is not in an open file you will of course not see
type highlighting, the same as you will see default colour for the type names
@b4n, the fact that its a constructor and would normally return an object of
that type is the far more important information, not that it happens to look
like a function call, thats just a distraction.
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