@linvinus so if a name is in a word list the style that sets overrides the style from the function call syntax? You should make that very clear in the submission to Scintilla.
In the case where the type is not in an open file you will of course not see type highlighting, the same as you will see default colour for the type names now. @b4n, the fact that its a constructor and would normally return an object of that type is the far more important information, not that it happens to look like a function call, thats just a distraction. -- You are receiving this because you are subscribed to this thread. Reply to this email directly or view it on GitHub: https://github.com/geany/geany/issues/1231#issuecomment-247561363
