@linvinus so if a name is in a word list the style that sets overrides the 
style from the function call syntax?  You should make that very clear in the 
submission to Scintilla.

In the case where the type is not in an open file you will of course not see 
type highlighting, the same as  you will see default colour for the type names 

@b4n, the fact that its a constructor and would normally return an object of 
that type is the far more important information, not that it happens to look 
like a function call, thats just a distraction.

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