If a variable name ends with "type", the symbol parser recognizes a symbol 
which does not exist. As an example, see the following code below:

> procedure plot_labels(iy,iy2: stipint; labtype: stipint);
const
  c_marker_type=1;
var
locdbg: boolean;
   {actual code}
end;

Which creates two functions: plot_labels (correct) and 1 (this is incorrect). 
See screenshot below:

![image](https://cloud.githubusercontent.com/assets/7198614/23316826/4c7ebeee-facc-11e6-8b4c-bda16d8b7855.png)


-- 
You are receiving this because you are subscribed to this thread.
Reply to this email directly or view it on GitHub:
https://github.com/geany/geany/issues/1409

Reply via email to