AlenkaF commented on issue #37517:
URL: https://github.com/apache/arrow/issues/37517#issuecomment-1715356785

   Sorry, I can not seem to create an example to reproduce the issue.
   Tried with dev version of `pyarrow`:
   
   ```python
   (pyarrow-dev) alenkafrim@Alenkas-MacBook-Pro python % python
   Python 3.10.10 (main, Feb 16 2023, 02:46:59) [Clang 14.0.0 
(clang-1400.0.29.202)] on darwin
   Type "help", "copyright", "credits" or "license" for more information.
   >>> import pyarrow as pa
   >>> pa.__version__
   '14.0.0.dev42+g1af709ff9.d20230830'
   
   >>> data = [[{'key': 'a', 'value': "1"}, {'key': 'b', 'value': "2"}], 
[{'key': 'c', 'value': "3"}]]
   
   >>> map_type = pa.map_(pa.string(), pa.string())
   >>> inner_map = pa.array(data, type=map_type)
   >>> inner_list = pa.ListArray.from_arrays([0, 1, 2], inner_map)
   >>> array = pa.MapArray.from_arrays([0, 1, 2], ["First", "Second"], 
inner_list)
   
   >>> table = pa.table({'array_element': array})
   >>> table.schema
   array_element: map<string, list<item: map<string, string>>>
     child 0, entries: struct<key: string not null, value: list<item: 
map<string, string>>> not null
         child 0, key: string not null
         child 1, value: list<item: map<string, string>>
             child 0, item: map<string, string>
                 child 0, entries: struct<key: string not null, value: string> 
not null
                     child 0, key: string not null
                     child 1, value: string
   >>> table.to_pandas()
                              array_element
   0  [(First, [[('a', '1'), ('b', '2')]])]
   1             [(Second, [[('c', '3')]])]
   ```
   
   ```python
   >>> table = pa.table({'array_element': inner_list})
   >>> table.schema
   array_element: list<item: map<string, string>>
     child 0, item: map<string, string>
         child 0, entries: struct<key: string not null, value: string> not null
             child 0, key: string not null
             child 1, value: string
   >>> table.to_pandas()
           array_element
   0  [[(a, 1), (b, 2)]]
   1          [[(c, 3)]]
   ```
   
   Can you check which column is giving you the error? Also, does the code 
above work for you?


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