bkietz commented on a change in pull request #10397: URL: https://github.com/apache/arrow/pull/10397#discussion_r660116713
########## File path: cpp/src/arrow/util/vector.h ########## @@ -84,27 +84,49 @@ std::vector<T> FilterVector(std::vector<T> values, Predicate&& predicate) { return values; } -/// \brief Like MapVector, but where the function can fail. -template <typename Fn, typename From = internal::call_traits::argument_type<0, Fn>, - typename To = typename internal::call_traits::return_type<Fn>::ValueType> -Result<std::vector<To>> MaybeMapVector(Fn&& map, const std::vector<From>& src) { +template <typename Fn, typename From, + typename To = decltype(std::declval<Fn>()(std::declval<From>()))> +std::vector<To> MapVector(Fn&& map, const std::vector<From>& source) { std::vector<To> out; - out.reserve(src.size()); - ARROW_RETURN_NOT_OK(MaybeTransform(src.begin(), src.end(), std::back_inserter(out), - std::forward<Fn>(map))); - return std::move(out); + out.reserve(source.size()); + std::transform(source.begin(), source.end(), std::back_inserter(out), + std::forward<Fn>(map)); + return out; } template <typename Fn, typename From, typename To = decltype(std::declval<Fn>()(std::declval<From>()))> -std::vector<To> MapVector(Fn&& map, const std::vector<From>& source) { +std::vector<To> MapVector(Fn&& map, std::vector<From>&& source) { std::vector<To> out; out.reserve(source.size()); - std::transform(source.begin(), source.end(), std::back_inserter(out), + std::transform(std::make_move_iterator(source.begin()), + std::make_move_iterator(source.end()), std::back_inserter(out), std::forward<Fn>(map)); return out; } +/// \brief Like MapVector, but where the function can fail. +template <typename Fn, typename From = internal::call_traits::argument_type<0, Fn>, + typename To = typename internal::call_traits::return_type<Fn>::ValueType> Review comment: there's not a good reason; just uniformity with getting `From` from call_traits. -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: github-unsubscr...@arrow.apache.org For queries about this service, please contact Infrastructure at: us...@infra.apache.org