goldmedal opened a new issue, #11551:
URL: https://github.com/apache/datafusion/issues/11551
### Is your feature request related to a problem or challenge?
After #10995, we have `parse_sql_expr()` to create a logical expression from
the SQL string. This API allows creating the expression with a `Schema`. I
tried to create the expression with a qualified schema:
```rust
let sql = "a < 5 OR a = 8";
let expr = col("t.a").lt(lit(5_i64)).or(col("t.a").eq(lit(8_i64)));
// provide type information that `a` is an Int32
let schema = Schema::new(vec![Field::new("a", DataType::Int32, true)]);
let df_schema = DFSchema::try_from_qualified_schema("t", &schema).unwrap();
let ctx = SessionContext::new();
let parsed_expr = ctx.parse_sql_expr(sql, &df_schema)?;
assert_eq!(parsed_expr, expr);
```
I expected the identifier to be `col("t.a")`, but it is actually `col("a")`.
I think the behavior can be aligned with the planning for the SQL statement:
```rust
ctx.register_batch("t", a_batch());
let df = ctx.sql("SELECT a < 5 OR a = 8 FROM
t").await?.into_optimized_plan()?;
dbg!(&df);
```
The result would be:
```
[datafusion-examples/examples/parse_sql_expr.rs:89:5] &df = Projection: t.a
< Int32(5) OR t.a = Int32(8) AS t.a < Int64(5) OR t.a = Int64(8)
TableScan: t projection=[a]
```
All of the identifiers are qualified.
### Describe the solution you'd like
I think we can find the field by `qualified_field_with_unqualified_name`,
and pass the qualifier when planning a column at
https://github.com/apache/datafusion/blob/28fa74bf0fb69f46fd03ef97eb301090de23b5f5/datafusion/sql/src/expr/identifier.rs#L50-L57
### Describe alternatives you've considered
_No response_
### Additional context
_No response_
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