alamb commented on code in PR #14888:
URL: https://github.com/apache/datafusion/pull/14888#discussion_r1971708109


##########
datafusion/optimizer/src/simplify_expressions/simplify_exprs.rs:
##########
@@ -122,14 +123,21 @@ impl SimplifyExpressions {
 
         // Preserve expression names to avoid changing the schema of the plan.
         let name_preserver = NamePreserver::new(&plan);
-        plan.map_expressions(|e| {
-            let original_name = name_preserver.save(&e);
-            let new_e = simplifier
-                .simplify(e)
-                .map(|expr| original_name.restore(expr))?;
+        let mut rewrite_expr = |expr: Expr| {
+            let name = name_preserver.save(&expr);
+            let expr = simplifier.simplify(expr)?;
             // TODO it would be nice to have a way to know if the expression 
was simplified
             // or not. For now conservatively return Transformed::yes
-            Ok(Transformed::yes(new_e))
+            Ok(Transformed::yes(name.restore(expr)))
+        };
+
+        plan.map_expressions(|expr| {
+            // Preserve the aliasing of grouping sets.

Review Comment:
   > What makes you think so?
   
   I was thinking that the  code skips calling `rewrite_expr` (which calls name 
preserver) for the GroupingSets (so thus does not preserve the aliases of the 
`Expr::Grouping` itself



##########
datafusion/optimizer/src/simplify_expressions/simplify_exprs.rs:
##########
@@ -122,14 +123,21 @@ impl SimplifyExpressions {
 
         // Preserve expression names to avoid changing the schema of the plan.
         let name_preserver = NamePreserver::new(&plan);
-        plan.map_expressions(|e| {
-            let original_name = name_preserver.save(&e);
-            let new_e = simplifier
-                .simplify(e)
-                .map(|expr| original_name.restore(expr))?;
+        let mut rewrite_expr = |expr: Expr| {
+            let name = name_preserver.save(&expr);
+            let expr = simplifier.simplify(expr)?;
             // TODO it would be nice to have a way to know if the expression 
was simplified
             // or not. For now conservatively return Transformed::yes
-            Ok(Transformed::yes(new_e))
+            Ok(Transformed::yes(name.restore(expr)))
+        };
+
+        plan.map_expressions(|expr| {
+            // Preserve the aliasing of grouping sets.

Review Comment:
   > What makes you think so?
   
   I was thinking that the  code skips calling `rewrite_expr` (which calls name 
preserver) for the GroupingSets (so thus does not preserve the aliases of the 
`Expr::Grouping` itself
   
   To be clear I think the code in PR looks good to me, I am just discussing if 
we can make the comment better



##########
datafusion/optimizer/src/simplify_expressions/simplify_exprs.rs:
##########
@@ -122,14 +123,21 @@ impl SimplifyExpressions {
 
         // Preserve expression names to avoid changing the schema of the plan.
         let name_preserver = NamePreserver::new(&plan);
-        plan.map_expressions(|e| {
-            let original_name = name_preserver.save(&e);
-            let new_e = simplifier
-                .simplify(e)
-                .map(|expr| original_name.restore(expr))?;
+        let mut rewrite_expr = |expr: Expr| {
+            let name = name_preserver.save(&expr);
+            let expr = simplifier.simplify(expr)?;
             // TODO it would be nice to have a way to know if the expression 
was simplified
             // or not. For now conservatively return Transformed::yes
-            Ok(Transformed::yes(new_e))
+            Ok(Transformed::yes(name.restore(expr)))
+        };
+
+        plan.map_expressions(|expr| {
+            // Preserve the aliasing of grouping sets.

Review Comment:
   > What makes you think so?
   
   I was thinking that the  code skips calling `rewrite_expr` (which calls name 
preserver) for the GroupingSets (so thus does not preserve the aliases of the 
`Expr::Grouping` itself



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