> HsParser does not allow method declarations to follow a default
> implementation of a method.
>
> class G a where
> f :: a -> a
> f x = x
> g :: a -> a
>
> Optional semicolons or empty statements are not permitted in
> do-expressions.
>
> f x = do ;; x ;
>
> That is probably the reason why this example fails to parse too:
>
> f x = do
> y
> where y = x
Thanks, both fixed.
Cheers,
Simon
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