| Do you mean if I have both an infinite loop and an error call, then I | might get only the loop?
Absolutely. f x = error "urk" loop n = loop (n+1) main = print (f (loop 0)) The compiler figures out that f is strict, and uses call by value. Result is a loop. Simon _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
