Hello folks, I seem to have hit this problem..
http://hackage.haskell.org/trac/ghc/ticket/1031 (I think, at least I'm getting a very similar incomprehensible error message :-) I tried using bang patterns instead of `seq` like this: > let a0_ = f a0 a in a0_ `seq` (# l,hl,a0_,r,hr #) becomes .. > let !a0_ = f a0 a in (# l,hl,a0_,r,hr #) but I still get the same error. Could someone who knows explain exactly what the problem is and what the workaround is (if there is one)? Thanks -- Adrian Hey _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
