No, there's no easy way (that I can see) to achieve what you want.  The problem 
is that the way to unpack C depends on how you instantiate 'a'.  So you need a 
specialised variant of the actual data constructor C, one for each 
instantiation of 'a'.  (Well, one for each "shape" of instantiation anyway.)

GHC doesn't currently generate specialised data constructors.  In principle one 
could do that, but it's not an easy step.

Simon

| -----Original Message-----
| From: [EMAIL PROTECTED] [mailto:glasgow-haskell-users-
| [EMAIL PROTECTED] On Behalf Of Takano Akio
| Sent: 15 November 2006 10:55
| To: [email protected]
| Subject: Unpacking polymorphic fields
|
| Hi,
|
| Suppose I have the following two datatypes.
|
| data B = B {-# UNPACK #-} !Int
| data C a = C {-# UNPACK #-} !Char !a
|
| If I have a strict function:
|
| printB :: B -> IO ()
| printB (B x) = print x
|
| test :: C B -> IO ()
| test (C c b) = print c >> printB b
|
|
| I want it to be worker-wrapper-transformed into:
|
| $wtest :: Char# -> Int# -> State# RealWorld -> (# State# RealWorld, () #)
|
| but GHC actually generates something like:
|
| $wtest :: Char# -> B -> State# RealWorld -> (# State# RealWorld, () #)
|
| The question is: is there any way to ask GHC to produce the former?
| If the field is not polymorphic, UNPACK pragma can be used for this, but
| it does not work in this case. If there is no such way, would
| it be a reasonable "feature request" to add one?
|
| Regards,
| Takano Akio
| _______________________________________________
| Glasgow-haskell-users mailing list
| [email protected]
| http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
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