> ... "constructor Foo has the type forall a . (Show a) => a".
Eh, of course I meant "the type forall a . (Show a) => a -> Foo", but you understood that I'm sure. :-) Cheers, /Niklas _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
