mechvel:
> People,
> I need to convert Char <-> Int in a possibly _standard_ way for
> Haskell -- and also in an efficient way. In particular, it must not
> spend 100 comparisons in a look through the listing of Char.
>
> I use ord :: Char -> Int and chr :: Int -> Char.
ord and chr are correct, yes.
ord :: Char -> Int
ord (C# c#) = I# (ord# c#)
chr :: Int -> Char
chr (I# i#) | int2Word# i# `leWord#` int2Word# 0x10FFFF# = C# (chr# i#)
| otherwise = error
"Prelude.chr: bad argument"
unsafeChr :: Int -> Char
unsafeChr (I# i#) = C# (chr# i#)
These are usually resolved at compile time as casts.
-- Don
_______________________________________________
Glasgow-haskell-users mailing list
[email protected]
http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
