On Wed, Aug 18, 2010 at 12:01:54PM +0200, Johan Tibell wrote: > > foldlWithKey' :: (b -> k -> a -> b) -> b -> Map k a -> b > foldlWithKey' f z0 m = go z0 m > where > go z Tip = z > go z (Bin _ kx x l r) = let x' = f (go z l) kx x in x' `seq` go x' r > > Could someone please explain the difference. I would like to be able > to to understand when I would get the former or the latter by looking > at the Haskell source.
If f is not strict in its first argument (e.g. if it always ignore it) then go is not strict in z. Thanks Ian _______________________________________________ Glasgow-haskell-users mailing list [email protected] http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
