my actual use case looks more like this:
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE FlexibleInstances, TypeSynonymInstances #-}
import Data.Text as T
class ShowT a where
showT :: a -> String
instance ShowT T.Text where
showT = show
instance ShowT String where
showT = show
main = print (showT "Hello!")
Ambiguous type variable `a0' in the constraints:
(ShowT a0) arising from a use of `showT' at default.hs:16:15-19
(Data.String.IsString a0) arising from the literal `"Hello!"'
So I actually want to define a default instance for a typeclass I
define that uses isString instances.
On Sat, Apr 21, 2012 at 6:24 PM, Daniel Peebles <pumpkin...@gmail.com> wrote:
> I think it'll be hard to do that without putting Text in base, which I'm not
> sure anyone wants to do.
>
> Dan
>
> On Sat, Apr 21, 2012 at 8:20 PM, Greg Weber <g...@gregweber.info> wrote:
>>
>> I would like to default IsString to use the Text instance to avoid
>> ambiguous type errors.
>> I see defaulting capability is available for Num. Is there any way to
>> do this for IsString?
>>
>> Thanks,
>> Greg Weber
>>
>> _______________________________________________
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>> Glasgow-haskell-users@haskell.org
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>
>
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