Hi, Am Freitag, den 08.07.2016, 13:09 +0200 schrieb Sven Panne: > I don't think so: https://ghc.haskell.org/trac/ghc/wiki/ArgumentDo#Bl > ockasaLHS explicit states that > > do f &&& g > x > > parses as > > (f &&& g) x
Correct
> , so
>
> foobar
> do f &&& g
> x
>
> parses as
>
> foobar ((f &&& g) x)
Where is the outer set of parenthesis coming from?
This is all not related to the ArgumentDo notation. Note that
(f &&& g)
x
parses as
(f &&& g) x
and still
foobar
(f &&& g)
x
parses as
foobar (f &&& g) x
just as
foobar
(f &&& g)
x
does.
(NB: I consider
foobar
arg1
arg2
bad style and prefer
foobar
arg1
arg2
but the former is allowed now and will be allowed later as well.)
Greetings,
Joachim
--
Joachim “nomeata” Breitner
m...@joachim-breitner.de • https://www.joachim-breitner.de/
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Debian Developer: nome...@debian.org
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