Hi Anthony, Maybe our Haskell'17 paper about Elaboration on Functional Dependencies sheds some more light on your problem: https://people.cs.kuleuven.be/~tom.schrijvers/Research/papers/haskell2017a.pdf
Cheers, Tom On Sat, Dec 8, 2018 at 6:42 AM Anthony Clayden <anthony_clay...@clear.net.nz> wrote: > On Fri, 7 Dec 2018 at 10:57 PM, Adam Gundry wrote: > >> >> Regarding inference, the place that comes to mind is Vytiniotis et al. >> OutsideIn(X): >> > > Thanks Adam for the references. Hmm That OutsideIn paper is formidable in > so many senses ... > > I'm not sure I grok your response on my specific q; to adapt your example > slightly, without a signature > > foo2 x@(_: _) = x > > GHC infers `foo2 :: [a] -> [a]`. That's not general enough. So I give a > signature with bare `b` as the return type, using the (~) to improve it: > > foo2 :: [a] ~ b => [a] -> b > > ... and GHC infers `foo2 :: [a] -> [a]`. Oh. Is that what I should expect? > > I'm chiefly concerned about improving bare tyvars under a FunDep. So to > take the time-worn example, I want instances morally equivalent to > > data TTrue = TTrue; data TFalse = TFalse > > class TEq a b r | a b -> r where tEq :: a -> b -> r > > instance TEq a a TTrue where tEq _ _ = TTrue > instance TEq a b TFalse where tEq _ _ = TFalse > > The FunDeps via CHRs 2006 paper tells me that first instance is supposed > to be as if > > instance (r ~ TTrue) => TEq a a r where ... > > but it isn't > > tEq 'a' 'a' :: TFalse -- returns TFalse, using the first pair of > instances > tEq 'a' 'a' :: TFalse -- rejected, using the (~) instance: > 'Couldn't match type TFalse with TTrue ...' > > The 'happily' returning the 'wrong' answer in the first case has caused > consternation amongst beginners, and a few Trac tickets. > > So what magic is happening with (~) that it can eagerly improve `foo2` but > semi-lazily hold back for `tEq`? > > Of course I lied about the first-given two instances for TEq: instances > are not consistent with Functional Dependency. So I need to resort to > overlaps and a (~) and exploit GHC's bogus consistency check: > > instance {-# OVERLAPPABLE #-} (r ~ TFalse) => TEq a b r where ... > > > ... like automatically inferring where `typeCast` needs to be placed > > Yes the non-automatic `TypeCast` version > > instance (TypeCast TTrue r) => TEq a a r where > tEq _ _ = TTrue -- rejected 'Couldn't match expected type > 'r' with actual type 'TTrue' ...' > > tEq _ _ = typeCast TTrue -- accepted > > Even though `typeCast` is really `id` (after it's jumped through the > devious indirection hoops I talked about). > > So what I'm trying to understand is not just "where" to place `typeCast` > but also "when" in inference it unmasks the unification. > > > AntC > > >> About your specific question, if a wanted constraint `a ~ b` can be >> solved by unifying `a` with `b`, then GHC is free to do so (in a sense, >> either parameter of (~) can be improved from the other). The real >> difference with `TypeCast` arises when local equality assumptions (given >> constraints) are involved, because then there may be wanted constraints >> that cannot be solved by unification but can be solved by exploiting the >> local assumptions. >> >> For example, consider this function: >> >> foo :: forall a b . a ~ b => [a] -> [b] >> foo x = x >> >> When checking the RHS of `foo`, a wanted constraint `[a] ~ [b]` arises >> (because `x` has type `[a]` and is used in a place where `[b]` is >> expected). Since `a` and `b` are universally quantified variables, this >> cannot be solved by unification. However, the local assumption (given >> constraint) `a ~ b` can be used to solve this wanted. >> >> This is rather like automatically inferring where `typeCast` needs to be >> placed (indeed, at the Core level there is a construct for casting by an >> equality proof, which plays much the same role). >> >> Hope this helps, >> >> Adam >> >> >> On 06/12/2018 12:01, Anthony Clayden wrote: >> > The (~) constraint syntax is enabled by either `GADTs` or `TypeFamilies` >> > language extension. >> > >> > GADTs/Assoc Data Types/Assoc Type Synonyms/Type Families arrived in a >> > series of papers 2005 to 2008, and IIRC the development wasn't finished >> > in full in GHC until after that. (Superclass constraints took up to >> > about 2010.) >> > >> > Suppose I wanted just the (~) parts of those implementations. Which >> > would be the best place to look? (The Users Guide doesn't give a >> > reference.) ICFP 2008 'Type Checking with Open Type Functions' shows >> > uses of (~) in user-written code, but doesn't explain it or motivate it >> > as a separate feature. >> > >> > My specific question is: long before (~), it was possible to write a >> > TypeCast class, with bidirectional FunDeps to improve each type >> > parameter from the other. But for the compiler to see the type >> > improvement at term level, typically you also need a typeCast method and >> > to explicitly wrap a term in it. If you just wrote a term of type `a` in >> > a place where `b` was wanted, the compiler would either fail to see your >> > `TypeCast a b`, or unify the two too eagerly, then infer an overall type >> > that wasn't general enough. >> > >> > (For that reason, the instance for TypeCast goes through some >> > devious/indirect other classes/instances or exploits separate >> > compilation, to hide what's going on from the compiler's enthusiasm.) >> > >> > But (~) does some sort of magic: it's a kinda typeclass but without a >> > method. How does it mesh with type improvement in the goldilocks zone: >> > neither too eager nor too lazy? >> > >> > >> > AntC >> >> >> _______________________________________________ > Glasgow-haskell-users mailing list > Glasgow-haskell-users@haskell.org > http://mail.haskell.org/cgi-bin/mailman/listinfo/glasgow-haskell-users > -- prof. dr. ir. Tom Schrijvers Research Professor KU Leuven Department of Computer Science Celestijnenlaan 200A 3001 Leuven Belgium Phone: +32 16 327 830 http://people.cs.kuleuven.be/~tom.schrijvers/
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