> 2016-09-21 20:56 GMT+02:00 Serkan Çoban <cobanser...@gmail.com>:
> > Then you can use 8+3 with 11 servers.
> 
> Stripe size won't be good: 512*(8-3) = 2560 and not 2048 (or multiple)

It's not really 512*(8+3) though.  Even though there are 11 fragments,
they only contain 8 fragments' worth of data.  They just encode it with
enough redundancy that *any* 8 contains the whole.
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