Hi

Depends on your system, but in principle yes.
A Cystein should be neutral. If you take a deprotonated one to build a complex with the zinc, it should be neutral afterwards.

Lets assume a case with HIS/HIS/CYS as complex partners. the resdiues without a complex are assumed to be neutral. Therefore, their charges added should be 0. Add your zinc to the complex, take a partial charge of 0.7xx for it and modify the charges of the complex partners (i.e. the S and in the case of histidine it makes sense to spread the charge difference over the ring). If you now add up all the charges of all complex partners, the system should again be at charge 0.
I can't see the problems, sorry.

Regards

Maik Goette, Dipl. Biol.
Max Planck Institute for Biophysical Chemistry
Theoretical & computational biophysics department
Am Fassberg 11
37077 Goettingen
Germany
Tel.  : ++49 551 201 2310
Fax   : ++49 551 201 2302
Email : mgoette[at]mpi-bpc.mpg.de
        mgoette2[at]gwdg.de
WWW   : http://www.mpibpc.gwdg.de/groups/grubmueller/


raja wrote:
Dear Mark,
Thanks for your reply. Well, I have well taken your point of making
separate charge group constituting Zn and its residues and I am working
out for it, in mean time I need some clarification in my present
approach.

I just detailed out my earlier mail hereunder.  I am using AMBER force
field.

This is default partial charge distribution for deprotonated Cystine
CYM N -0.4157 CYM H 0.2719 CYM CA -0.0351 CYM HA 0.0508 CYM CB -0.2413 CYM HB1 0.1122 CYM HB2 0.1122 CYM SG -0.8844 CYM C 0.5973 CYM O -0.5679 ------------------------
Formal Charge = -1.00000
----------------------------

Now my modified partial charge at SG to -0.6944

CYM N -0.4157 CYM H 0.2719 CYM CA -0.0351 CYM HA 0.0508 CYM CB -0.2413 CYM HB1 0.1122 CYM HB2 0.1122 CYM SG -0.6944 CYM C 0.5973 CYM O -0.5679 ------------------------
Formal Charge = -0.8100
-----------------------

According to manual, to ensure integer value of total charge on the
residue CYM (cysteine). Ideally, following the force field convention, I
would like to do readjustment of the individual partial charges to make
it as total =  -1. But on other hand this is my intuition that, formal
charge for -1 for CYM is applicable for free Cysteine residue in AMBER
force field, but in my case, it is harmonically bonded with zinc and
also the charge transfer is taken place. This makes me to think that the
formal charge of CYM should be adjusted to neutral. Please give your
thought?

With thanks !
B.Nataraj











On Tue, 28 Nov 2006 17:51:04 +1100, "Mark Abraham"
<[EMAIL PROTECTED]> said:
raja wrote:
Hi gmxions,
There are many references, say that Zn2+ partial charge should be
reduced to ~0.7 rather than the force field default value of 2. In line
with that there are many values published for distributed charge in its
surrounding ligand atoms in compensation for loss of positive charge of
Zn.
OK, so this strategy preserves charge neutrality over the zinc and a bunch of ligand residues. It will not preserve charge neutrality of the individual residues, obviously.

Now I am having set of values to be distributed for my system's
active site residues, say for one SG-Cys, and two NE2-His atoms. My
question is that what will be net formal charge for these residues after
its specific atoms' charges are modified.
The old value, plus the modification?

In other words, for example,
after modifying default partial charge of SG-Cys from  -0.8844 to
-0.6944, Should I adjust its net formal charge to -1 or to 0?
Not sure where you're adjusting the "net formal charge" or why you think it's necessary.

What you really want to do is have charge groups with integral values of charge (see section 3.4.2 and some part of Chapter 5 for how to do this), so that probably means combining the zinc with chunks of these residues into one large +2 charge group.

Then on
what basis I can adjust rest of the atoms&#8217; partial charges.
Why would you do this? Whatever you do should be consistent with the most reliable scheme in the literature, unless you want to create an expensive random number generator.

Mark
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