2008-12-05



刘鑫



发件人: 刘鑫
发送时间: 2008-12-05 11:30:41
收件人: [EMAIL PROTECTED]
抄送: 
主题: help: how to set up a rigid system


Dear GMX users,


I am carrying out MD simulation of acetylacetone by Gromacs. As we know, there 
are keto and enol two tautomers for acetylacetone. The tautomers were treated 
as rigid species in the literature (Y.K. Park, C. H. Turner, J. Supercrit. 
Fluids 37 (2006) 201–208)). The parameters of the LJ interactions and the 
electrostatic interactions of keto and enol models for acetylacetone and their 
equilibrium geometry were given. Dihedral angles are included in the models to 
specify the keto geometry, while the enol form is calculated to be a planar 
molecule. 

 Model parameters 
Molecule               Site         q/e    σ (nm)  ε/kb (K)          Geometry
Acetylacetone (Keto)   
                            CH3        −0.12    0.396    73.02    C-C: 0.151 
nm, ∠CCCH2: 116.7◦   
                                                                           
∠CCO: 123.1◦, ∠CCCH2C: −81.7◦
                       C=           0.48    0.375    52.876        C-CH2: 0.152 
nm, ∠CCH2C: 111.7◦,
                                                                            
∠CCH2CC: −162.1◦

                       O=          −0.34    0.296    105.75        C=O: 0.122 nm
                     -CH2-          0.0     0.3905    59.42         CH2-C: 
0.153 nm, ∠CH2CO: 122.0◦
                                                                              
∠CH2CC: 115.4◦
                      C=            0.52     0.375     52.876         C=O: 
0.122 nm, C-CH3: 0.151 nm
                       O=          −0.32    0.296     105.75
                       CH3         −0.22    0.396     73.02

Acetylacetone (E)      O          −0.366    0.300    85.609          O-C: 0.133 
nm, ∠OCC(H3): 113.6◦
                       H(-O-)       0.411    0.0       0.0            H-O: 
0.099 nm, ∠HOC: 105◦
                       C(-OH)       0.303    0.375    52.876         C-CH3: 
0.150 nm, C=CH: 0.137 nm
                       CH3        −0.173    0.391    80.573        ∠CH3C(-O)C: 
124.2◦
                       CH            0.197   0.380     57.912      ∠CC(H)C: 
120.5◦, C C( O): 0.145nm,
                                                                              
∠C(H)C=O: 121.6◦, ∠CC(=O)CH3: 121.6◦
                       C(=O)        0.360     0.375    52.876     C=O: 0.125 
nm, CCH3: 0.151 nm
                       CH3        −0.258     0.391     80.573
                       O=        −0.474      0.296     105.75 


 But I could not know how to set up this rigid system in gromacs. If you could 
give me some advice or some material, I will appreciate it. Thank you!
2008-12-05 


Dr. Xin Liu,

School of Chemistry and Chemical Engineering

Sun Yat-Sen University

No.135, Xingang Xi Road,

Guangzhou, 510275

P. R. China

Tel.: +86-20-84115559

Fax: +86-20-84112245

E-mail: [EMAIL PROTECTED] mailto:[EMAIL PROTECTED]
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