----- Original Message -----
From: Moeed <[email protected]>
Date: Monday, August 30, 2010 9:09
Subject: [gmx-users] energy unit
To: [email protected]

> Dear Justin,
> 
> Thanks for your explanation. I am sorry to bother you again. Like you said: 
> "a mole of a given species in the given configuration would have this energy 
> in kJ". This is absolutely clear but actually I think increasing the total 
> energy with system size contradict this statement unless values given by 
> g_energy are in KJ/system. If there are more interactions in a bigger system, 
> as you said eventually values refer to mole number of particles (regardless 
> of number of particles). If there are half  Na (avogardo) particles, finally 
> energy is multiplied by 2 to get KJ/mole and if there are 10*Na, g_energy 
> divides total energy by 10. Please enlightem me on this issue. Many thanks

To say that "the energy of a single-component system is in kJ/mol" is to say 
that if (somehow) a mole of that component were present in the system in that 
configuration, then the energy would be that number in kJ.

If the system was twice as large, the magnitude of the energy in kJ/mol does 
increase, because there are more interactions. If a mole of that system were 
present, then its energy would be that number in kJ. This appears to generate a 
contradiction, however there is a size dependence in the energy that is not 
linear in the number of molecules, so that this comparison is between two 
different kinds of quantities.

To compare these two cases, you need to normalize not by the number of 
particles, but by the number of interactions.

Think about building up a LJ-only system of a noble gas in an infinite 
non-periodic system. With one atom, the energy is zero. With two atoms, the 
energy from the single interaction is normally non-zero, and has some value if 
you average it over all possible configurations. It doesn't matter whether you 
measure it in Hartree, or kJ, or kJ/mol - these are just multiplication by a 
conversion constant. With three atoms, there are now three interactions, the 
configurational-average energy has greater magnitude - but it makes no sense to 
compare these last two cases without normalizing by the number of interactions. 
When you do that normalization, then the numbers will almost agree - because 
the total energy was a simple sum of three nearly independent components 
(except that the atoms could not coincide). The same kind of thinking goes for 
the kind of systems the OP was originally considering, but there are more 
complications from the number and kind of interactions.

Mark

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