About the red curve, I guess fluctuations might be directly related to volume fluctuations, you can extract the volume over time from g_energy (boxXX*boxYY**boxZZ) and compare. (just another comment, now I am not very sure about the "f." that precedes the red line legend..)

About the interpretation of the quantities, the Widom technique does not provide you with an absolute value of the chemical potential but directly with the excess chemical potential. So, mu=-kTlog(Ve ^ (U*B)/(V))n+1 is the excess chemical potential, where (if I recall correctly) U_{n+1} is the the interaction energy between the inserted particle and the rest of the system. You don't need (and should not do) such post-processing operations that you proposed to get the excess chemical potential.

Javier


El 16/05/12 11:06, Steven Neumann escribió:
Thank you very much! I just saw your response.

As I run it in NPT ensemble the plot with volume is important for me. Please, See the plot:

http://speedy.sh/CJn5b/tpiN.jpg

So does the fluctuating red curve make any sesnse then if it does not consider volume?

Another thing: this is chemical potential of the system with extra water molecule (N+1), right (u=-kTlog(Ve ^ (U*B)/(V))n+1? So if I want to obtain the excess chemical potential: u=-kTlog(Ve ^ (-deltaU*B)/(V)) I should calculate it for the system with N molecules and then substract it. Is it calculated somewhere or I should use g_energy of my previosu system and calculate the total potential energy then -kTlog... of this values and then substract it? Please correct me if I am wrong.

Steven


On Tue, May 15, 2012 at 11:59 AM, Javier Cerezo <[email protected] <mailto:[email protected]>> wrote:

    Hi Steven.


    1. Why this value is divided by nm3? Shall I multiply it by the
    simulation box?
    It is not not divided by nm3. The legend for "y" axis is not
    appropriate for your plot. Keep in mind that the same graph is
    used to represent lots of quantities (you can plot all of them
    with xmgrace -nxy tpi.xvg). The "y" axis is not the same for all,
    but only one label is possible, so developers have to chose which
    label to place on the axis. But this is just a label, don't give
    much importance to it and analyse you results (including units)
    according to the equations and the standard units in gromacs.

    2. Why e^(-BU) is multiplied by V? I just want to have the excess
    chemical potential: u=-kTlog(e ^ (-deltaU*B) - so how can I get
    deltaU?
    The volume appears in the expression of the excess chemical
    potential if you are running a NpT ensemble. The second plot (if
    you use xmgrace -nxy tpi.xvg) does not contain the volume.

    3. The value corresponds to the plateau so I should run it for
    longer time?
    You are getting a time&ensemble average and for large sampling
    (and large simulation times), this average should converge. So,
    the final value you will get is the last point of the graph, it up
    to you to say if it is converged. So you can try to enlarge the
    number of points sampled, if the shape does not change you are
    sampling correctly every snapshot, then take longer simulation
    times if you want to converge your results.

    Javier


    El 15/05/12 09:57, Steven Neumann escribió:


    On Mon, May 14, 2012 at 5:05 PM, Justin A. Lemkul
    <[email protected] <mailto:[email protected]>> wrote:



        On 5/14/12 11:53 AM, Steven Neumann wrote:

            Dear Gmx Users,

            Did anyone use TPI method for the calculation of chemical
            potential? The tpi.xvg
            files consists of:

            @ s0 legend "-kT log(<Ve\S-\xb\f{}U\N>/<V>)"
            @ s1 legend "f. -kT log<e\S-\xb\f{}U\N>"
            @ s2 legend "f. <e\S-\xb\f{}U\N>"
            @ s3 legend "f. V"
            @ s4 legend "f. <Ue\S-\xb\f{}U\N>"
            @ s5 legend "f. <U\sVdW System\Ne\S-\xb\f{}U\N>"
            @ s6 legend "f. <U\sdisp c\Ne\S-\xb\f{}U\N>"
            @ s7 legend "f. <U\sCoul System\Ne\S-\xb\f{}U\N>"
            @ s8 legend "f. <U\sCoul recip\Ne\S-\xb\f{}U\N>"

            @    xaxis  label "Time (ps)"
            @    yaxis  label "(kJ mol\S-1\N) / (nm\S3\N)"

            Can anyone explain me these legends? I just want obtain a
            value of the excess
            chemical potential according to the equation:
            u=-kT log (-deltaV/kT), Which legend is responsible for
            this and what are the
            units? kJ/mol? Please, explain as the above letters does
            not mean to me anything?


        These strings are formatted for XmGrace.  Have you tried
        plotting the file to see what it contains?  The legends will
        be far more obvious if you do.

        -Justin


    Thank you Justin.
    Can anyone explain me from the plot:

    http://speedy.sh/Xpnws/tpi.JPG

    1. Why this value is divided by nm3? Shall I multiply it by the
    simulation box?
    2. Why e^(-BU) is multiplied by V? I just want to have the excess
    chemical potential: u=-kTlog(e ^ (-deltaU*B) - so how can I get
    deltaU?
    3. The value corresponds to the plateau so I should run it for
    longer time?


    Thank you,

    Steven


-- ========================================

        Justin A. Lemkul, Ph.D.
        Department of Biochemistry
        Virginia Tech
        Blacksburg, VA
        jalemkul[at]vt.edu <http://vt.edu> | (540) 231-9080
        <tel:%28540%29%20231-9080>
        http://www.bevanlab.biochem.vt.edu/Pages/Personal/justin

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-- Javier CEREZO BASTIDA
    PhD Student
    Physical Chemistry
    Universidad de Murcia
    Murcia (Spain)
    Tel: (+34)868887434 <tel:%28%2B34%29868887434>

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Javier CEREZO BASTIDA
Ph.D. Student
Physical Chemistry
Universidad de Murcia
30100, Murcia (SPAIN)
T: (0034)868887434

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