On Wed, Aug 08, 2007 at 06:03:37PM -0700, David Rorex wrote:
> On 8/8/07, Paul Smedley <[EMAIL PROTECTED]> wrote:

> Why is it even calling ceil on an int in the first place? I think you should
> be able to simply do: (regardless of platform)
> 
>         in->ensureBytes( sample_count * ( 3 + n_bits/8 );

It's not calling ceil on an int, but on the result of a division.
We want to get 1 if n_bits is 6 ...

ceil(n_bits/8)

--strk;


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