On 4/28/21 5:57 PM, Bruce Labitt wrote:
> If someone could suggest how to do this, I'd appreciate it. I've
> scraped a table of fine thread metric screw parameters from a website.
> I'm having some trouble with regex (re) separating the numbers. Have
> everything working save for this last bit.
>
> Here is a sample string:
>
> r1[1] = ' 17.98017.87417.65517.59917.43917.291'
>
> I'm trying to separate the numbers. It should read like this:
>
> 17.980, 17.874, 17.655, 17.599, 17.439, 17.291
>
> There's more than 200 lines of this, so it would be great to automate
> it! Each number has 3 digits of precision, so I want to add a comma and
> a space after the third digit.
>
> re.search('(\.)\d{3,3}', r1[1]) returns
> <re.Match object; span=(3, 7), match='.980'> so it found the first instance.
>
> But, re.sub('(\.)\d{3,3}', '(\.)\d{3,3}, ', r1[1]) yields a KeyError:
> '\\d' (Python3.8). Get bad escape \d at position 4.
The second argument [the replacement string] to re.sub(pattern, repl, string)
is not supposed to
just be a variation of the pattern-matching string that you passed as the first
argument.
I think the best illustration that I can give here is to just fix this up for
you:
re.sub(r'(\.)(\d{3,3})', r'\1\2, ', r1[1])
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