On Thu, 18 Apr 2002, at 9:17pm, Paul Iadonisi wrote:
> The 'date +%j' command returns a number with a leading zero. To the 'let'
> assignment this looks like an octal number, but the digit '9' is 'too
> great for base' (base being 8). Haven't found an elegant way to fix it
> yet, if I figure it out, I'll 'let' you know ;-).
When all else fails, RTFM. :-) Mine tells me (under "ARITHMETIC
EVALUATION") that:
Constants with a leading 0 are interpreted as octal num-
bers. A leading 0x or 0X denotes hexadecimal. Otherwise,
numbers take the form [base#]n, where base is a decimal
number between 2 and 64 representing the arithmetic base,
and n is a number in that base.
So, if you do this
let due=10#`date +%j -d 04/01/2002`
it forces bash to evaluate the "091" in base 10, and it works.
While we are on the subject of shell programming, it is better to use this
let due=10#$(date +%j -d 04/01/2002)
construct. The $(...) syntax can be nested, and is easier to read than the
`...` syntax.
--
Ben Scott <[EMAIL PROTECTED]>
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