On Wed, Mar 16, 2005 at 11:07:27AM -0800, Tom Lord wrote: > You argue that while one function will certainly be broken, > it is unlikely that two functions will be broken at the same > time. > > But logically speaking, the combination of two hash functions > is a single hash function. It is just as "a priori" likely > that the combination will be broken.
You can't restate temporal logic in classical predicate logic that way and come up with a correct conclusion. It is very unlikely that the combination will be broken *simultaneously*, and a non-simultaneous break is not a vulerability. -- .''`. ** Debian GNU/Linux ** | Andrew Suffield : :' : http://www.debian.org/ | `. `' | `- -><- |
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