I have the following version: 130 [EMAIL PROTECTED]:~/Personal/src/gpgstats$ dpkg --list | grep gpgme ii libgpgme11 1.0.2-1 GPGME - GnuPG Made Easy ii libgpgme11-dev 1.0.2-1 GPGME - GnuPG Made Easy ii libgpgme6 0.3.16-2 GPGME - GnuPG Made Easy
lrwxrwxrwx 1 root root 18 Apr 14 08:27 /usr/lib/libgpgme.so ->
libgpgme.so.11.3.3
lrwxrwxrwx 1 root root 18 Apr 14 08:26 /usr/lib/libgpgme.so.11 ->
libgpgme.so.11.3.3
-rw-r--r-- 1 root root 127368 Jan 15 15:27 /usr/lib/libgpgme.so.11.3.3
lrwxrwxrwx 1 root root 17 Apr 3 02:12 /usr/lib/libgpgme.so.6 ->
libgpgme.so.6.3.7
-rw-r--r-- 1 root root 99184 May 1 2004 /usr/lib/libgpgme.so.6.3.7
I'm doing:
(void)gpgme_check_version(NULL);
err = gpgme_new(&ctx);
err = gpgme_op_keylist_start (ctx, NULL, 0);
err = gpgme_op_keylist_next(ctx, &r_key);
gpgme_user_id_t uids = r_key -> uids;
...for each uid...
gpgme_key_sig_t sigs = uids -> signatures;
Now sigs in this case is *always* NULL!
And I've verified (with gpg --list-sigs) that *all* keys have one or more
signature.
Oh, and do I need to free-up something after I do gpgme_op_keylist_next?
Folkert van Heusden
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