On Mon, Jul 20, 2009 at 10:09:03AM +0200, Nix wrote: > Hello, > > I have a problem with gpg (GnuPG) 1.4.9 > > I got three keys. I receive a crypted file and when i want to decrypt gpg > don't want to use another key than the default. > > i use this commande > > gpg -u 5E95FE19 -d 00poap/gpg > > Can you help me plz.
That should be "gpg -k 5E95FE19 -d 00poap/gpg", not "-u". Either use -u 'Real Name' or -k keyid; in this case, 5E95FE19 is the key ID, not the user ID attached to this key. G'luck, Peter -- Peter Pentchev [email protected] [email protected] [email protected] PGP key: http://people.FreeBSD.org/~roam/roam.key.asc Key fingerprint FDBA FD79 C26F 3C51 C95E DF9E ED18 B68D 1619 4553 What would this sentence be like if it weren't self-referential?
pgpqT3R77Q5mf.pgp
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