Niibe-san
Thank you so much for your help! It worked.
I was using gpg4win, which of course does not include v2.1. I need to download
the windows version from gnupg.org.
I had some difficulty with the syntax of a windows batch file but eventually
succeeded with
gpg-connect-agent.exe --run <FILE>
Where <FILE> contained:
OPTION pinentry-mode=loopback
/definqfile PASSPHRASE <PIN>
SCD CHECKPIN <CARDID>
/bye
And where <CARDID> was the ID of the card from gpg --card-status as you
suggested,
and <PIN> was a file containing the PIN.
Thank you again for your kind advice.
-----Original Message-----
From: Gnupg-users [mailto:gnupg-users-boun...@gnupg.org] On Behalf Of NIIBE
Yutaka
Sent: 02 December 2015 03:07
To: gnupg-users@gnupg.org
Subject: Re: Provide user PIN to gpg-agent?
On 12/01/2015 10:50 PM, Harbord Jonathan-EURITEC wrote:
> Is it possible to pass the user PIN of a smartcard to gpg-agent in a command?
>
> I'd like to stop the pinentry program appearing for an automated system.
Please note that I don't have any experience like that, and I don't generally
recommend such a usage.
In general, we can provide a special application specific pinentry program for
such a special purpose.
In GnuPG 2.1.x, there is allow-loopback-pinentry option. When enabled it by
.gnupg/gpg-agent.conf or as an argument invoking gpg-agent, we can do something
like:
gpg-connect-agent \
"OPTION pinentry-mode=loopback"
'/definqfile PASSPHRASE /tmp/passphrase-for-smartcard' \
"SCD CHECKPIN <CARDID>" /bye
having a file /tmp/passphrase-for-smartcard, where <CARDID> is the one in the
output of 'gpg --card-status' like:
Application ID ...: D276000124010200F517000000010000
Substitute <CARDID> by D276000124010200F517000000010000.
Please try.
--
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