package main
func main() {
var m map[int]int
{
m = make(map[int]int)
}
_ = m
}
if I do this m will not escape just want to know what's the scope rule for
escape ? puzzled
<http://www.baidu.com/link?url=ApC817U9uUoCFHhS_dqb5JzUWJQsslUUA6_TDv3LDZBJgaA-G2ZbRfWA-2cGajgU_MHmTiXVEouMmdPN53mMMXxYd1nvCWWJJvfu5Mmg4Ca>
在 2016年9月29日星期四 UTC+8上午1:39:09，Chris Manghane写道：
>
> In the first example, make does not escape the scope of the for statement.
> In the second example, make is assigned to m, which is outside of the scope
> of the for statement, which means the make operation escapes its scope and
> subsequently, is heap allocated. If you want more information about why
> something escapes, try compiling with -gcflags "-m -m" for an explanation
> of the escape analysis information.
>
> On Wed, Sep 28, 2016 at 7:56 AM, 刘桂祥 <liuguix...@gmail.com <javascript:>>
> wrote:
>
>> go 1.7
>>
>> 在 2016年9月28日星期三 UTC+8下午10:41:09，Dave Cheney写道：
>>
>>> Which version of Go?
>>>
>>> On Thursday, 29 September 2016 00:18:29 UTC+10, 刘桂祥 wrote:
>>>>
>>>> // example1.go
>>>> package main
>>>>
>>>>
>>>> func main() {
>>>>
>>>> for i := 0; i < 2; i++ {
>>>> m := make(map[int]int)
>>>>
>>>>
>>>>
>>>> m[1] = 100
>>>> }
>>>>
>>>>
>>>> }
>>>>
>>>>
>>>> main make(map[int]int) does not escape
>>>>
>>>>
>>>> // example2.go
>>>> package main
>>>>
>>>>
>>>> func main() {
>>>> var m map[int]int
>>>> for i := 0; i < 2; i++ {
>>>> m = make(map[int]int)
>>>>
>>>>
>>>>
>>>> m[1] = 100
>>>> }
>>>>
>>>>
>>>> }
>>>>
>>>> make(map[int]int) escapes to heap why ???
>>>>
>>>>
>>>> --
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>
>
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