In Java, if an interface contains exactly one method, and that method is not already part of java.lang.Object, the syntax
Interface i = (arguments) -> { code }; will make an object i of that interface type with the given closure as the method body. This interface is called a functional interface. Pre-Java 8, the same thing could be done with Interface i = new Interface() { public void method() { code } }; These interface literals are different from Go's interface literals. > On Oct 8, 2016, at 11:24 AM, Jan Mercl <0xj...@gmail.com> wrote: > > > > On Sat, Oct 8, 2016, 16:39 Pietro Gagliardi <andl...@lostsig.net > <mailto:andl...@lostsig.net>> wrote: > > > Go does not have functional interfaces or interface literals. > > I don't know what is meant by 'functional interfaces' but Go definitely > supports interface literals. > > -- > -j > > > -- > You received this message because you are subscribed to the Google Groups > "golang-nuts" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to golang-nuts+unsubscr...@googlegroups.com > <mailto:golang-nuts+unsubscr...@googlegroups.com>. > For more options, visit https://groups.google.com/d/optout > <https://groups.google.com/d/optout>. -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.