On Thu, Oct 13, 2016 at 2:42 PM <d...@veryhaha.com> wrote:
> I don't understand the comment of the last line. Can someone explain it
"r has type io.Reader" means that the type if expr.(T) is T.
"and y must implement both I and io.Reader"
y is either nil or it implements I, because that's how it was declared and
nothing not implementing I can be assigned to it. The dynamic type of y can
implement any number of interfaces, so it can implement both I and
io.Reader. The later is checked at run time when the type assertion
expression y.(io.Reader) is actually evaluated.
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