Under the generics draft, would this be allowed?
type Foo(type T) struct{}
func f(x Foo(int)) {}
I assume the answer is yes; I can't see any good reason to disallow it.
What about this?
func (x Foo(int)) Bar() {}
If this is allowed, does this now mean that Foo(int) implements
type Barrable interface {
Bar()
}
but that Foo(float64) does not implement Barrable?
What about this, where V is meant to be a type parameter, not a specific
type that was defined earlier in the code? (If allowed, it probably needs a
'type V' in it somewhere, but I'm not sure where to put that.)
func (x Foo([]V)) Bar() {}
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