Note that this would still accept numeric literals:
w.At(4)
If you want to avoid this, you can wrap the index type in a struct:
type Index struct {
I int
}
Quoting Ian Denhardt (2018-10-07 13:20:48)
> Yeah, there's no way to do this as such. One thing you could possibly do
> instead is define a wrapper around the type and use methods:
>
> type MyWrapper struct {
> theSlice []Elem
> }
>
> type Index int
>
> func(w MyWrapper) At(i Index) Elem {
> return w.theSlice[int(i)]
> }
>
> func(w MyWrapper) SetAt(i Index, v Elem) {
> w.theSlice[int(i)] = v
> }
>
> Quoting jake6...@gmail.com (2018-10-07 09:29:23)
> > I'm gonna say no.
> > On Saturday, October 6, 2018 at 5:07:33 PM UTC-4, Steve Roth wrote:
> >
> > Is there a way to declare an array (or slice) that is indexed by a type
> > derived from int, rather than indexed by int?� My intent is to have
> > the compiler complain if I index the array/slice with a generic int
> > rather than the specific int-derived type I'm supposed to use.� This
> > will help verify correct usage of the array.� I didn't see any way to
> > do this in the language spec, but hopefully I just missed it?
> > Thanks,
> > Steve
> >
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