true:
a := &T{Name:"test", Child: &T{Name: "blah", Child: nil}}
b :=&T{Name:"test", Child: a.Child}
and it's not "childs"
пятница, 23 ноября 2018 г., 6:20:31 UTC+3 пользователь Jesse McNelis
написал:
>
> On Fri, Nov 23, 2018 at 2:06 PM Youqi yu <yuyouq...@gmail.com
> <javascript:>> wrote:
> >
> > type T {
> > Name string
> > }
> > a := &T{Name:"test"}
> > b :=&T{Name:"test"}
> > *a == *b
> > Hi, all, I am beginner at golang, I have a question that when compare
> struct equality, I was told to use reflect.DeepEqual or make my own
> function. but the result of above code is true. Does it mean struct a
> equals struct b?
>
> Yes, they are equal. But how the equality is decided may not always be
> what you want.
> eg.
>
> type T {
> Name string
> Child *T
> }
> a := &T{Name:"test", Child: &T{Name: "blah", Child: nil}}
> b :=&T{Name:"test", Child: &T{Name: "blah", Child: nil}}
> *a == *b // false
> reflect.DeepEqual(a,b) //true
>
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