Thanks, David. Let me look into passing as a parameter.
Actually, I didn't paste all the code. My array in the for loop does have
a check that if array limit is reached, I set the index to zero and
overwrite data. Thus, the last 65536 entries are looked at.
Hemant
On Saturday, February 16, 2019 at 3:16:54 PM UTC-5, David Riley wrote:
>
> I suspect it's because your reference to the time_array is actually
> copying it into your closure that's running as the goroutine instead of
> making a reference to it. You might do better to pass that array as a
> parameter to the goroutine instead of trying to absorb it as context.
>
> I should note that your approach of filling a statically sized array is
> probably not the best one, because that's going to eventually panic once
> you hit the limit. But that's a bit out of scope of this discussion, and
> I'm sure you mostly meant it for illustrative purposes.
>
>
> - Dave
>
>
> > On Feb 16, 2019, at 9:29 AM, Hemant Singh <heman...@gmail.com
> <javascript:>> wrote:
> >
> > I have the following program. The program is processing network packets
> at 1 Gbps rate. I don't want to print the rate for every packet. Instead,
> I'd like to save the rate in an array and dump the array on Ctrl-c of the
> program. When I dump the array on Ctrl-c, the data is all zeroes. Please
> see "<===" in the program below. Anything else one could do?
> >
> > Thanks.
> >
> > -Hemant
> >
> > func main() {
> >
> > const SZ = 65536
> > var time_array [SZ]float64
> >
> > c := make(chan os.Signal)
> > signal.Notify(c, os.Interrupt, syscall.SIGTERM)
> >
> > go func() {
> > <-c
> > fmt.Printf("You pressed ctrl + C. User interrupted infinite loop.")
> > fmt.Printf("%v ", time_array); <=== all zeroes printed.
> > os.Exit(0)
> > }()
> >
> >
> > i := 0
> > for {
> > ...
> > time_array[i] = rate
> > fmt.Printf("%f bps ", rate) <=== value printed is correct.
> > i++
> > }
> > }
>
>
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