On Saturday, September 14, 2019 at 11:04:06 AM UTC-4, Axel Wagner wrote: > > Can you explain more specifically what you don't understand? > The example seems pretty clear: Say you currently require the latest > master commit (e.g. by using a pseudo-version), which is a couple commits > ahead of the latest released version, then "latest" will select the > release, while "upgrade" will select the current commit. >
Do you mean if there is already a require line in the go.mod file, which requires a non-formal tagged version, then "go get ...@latest" will rollback the require to the latest formal tagged version, but "go get ...@upgrade" will not? > > On Sat, Sep 14, 2019 at 10:35 AM T L <tapi...@gmail.com <javascript:>> > wrote: > >> The doc https://golang.org/cmd/go/#hdr-Module_queries says: >> >> The string "upgrade" is like "latest", but if the module is currently >>> required at a later version than the version "latest" would select (for >>> example, a newer pre-release version), "upgrade" will select the later >>> version instead. >>> >> >> But I don't very get it. Who can explain it more to let me understand it >> better? >> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "golang-nuts" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to golan...@googlegroups.com <javascript:>. >> To view this discussion on the web visit >> https://groups.google.com/d/msgid/golang-nuts/6a4ace13-3ad8-4154-846c-e8d5f343b022%40googlegroups.com >> >> <https://groups.google.com/d/msgid/golang-nuts/6a4ace13-3ad8-4154-846c-e8d5f343b022%40googlegroups.com?utm_medium=email&utm_source=footer> >> . >> > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/f17a504d-95da-46b4-ad0c-3b544e579176%40googlegroups.com.
