Sorry again. Well, I followed your advice. Here is the link https://play.golang.org/p/7DigEVsKbdx How can I cancel goToSleep() when timeout is reached?
El lunes, 24 de febrero de 2020, 14:16:32 (UTC-3), Jake Montgomery escribió: > > Your code will still not compile. In this group, it is often helpful to > include a link to your code in the playground (https://play.golang.org/) > using the "Share" button. That is in addition to, or instead of, posting > your code in the message. This will allow others to easily run your code, > but also will allow you to make sure it compiles. > > On Monday, February 24, 2020 at 10:01:01 AM UTC-5, Juan Mamani wrote: >> >> Sorry}, here is the right code: ( just was the effect to b working til >> At 5:20am sleepy and lost) >> >> Expected behaviour is to end anonyimous func when 3s timeout is >> reached. >> >> //------------------------------------------------ >> package main >> >> import( >> //"fmt" >> "time" >> "math/rand" >> "log" >> ) >> >> func main(){ >> >> for{ >> log.Println("-----------------Start") >> Task() >> log.Println("-----------------End") >> >> } >> >> } >> >> >> // Trying to adapt from Concurrency in Go by Katherine Cox-Buday >> func Task(){ >> >> doWork := func( done <-chan interface{}, strings <-chan string, ) <-chan >> interface{} { //1 >> terminated := make(chan interface{}) >> go func() { >> defer log.Println("doWork exited.") >> defer close(terminated) >> for { >> goToSleep() >> select { >> //case s := <-strings: >> // case s := ran(): >> // Do something interesting >> //fmt.Println(s) >> case <-done: //2 >> return >> } >> } >> }() >> return terminated >> } >> >> done := make(chan interface{}) >> terminated := doWork(done, nil) >> >> go func() { //3 >> // Cancel the operation after 3 second. >> time.Sleep(3 * time.Second) >> log.Println("Canceling doWork goroutine reach 3s...") >> close(done) >> }() >> >> <-terminated //4 >> log.Println("Done.") >> } >> >> done := make(chan interface{}) >> terminated := doWork(done, nil) >> >> go func() { //3 >> // Cancel the operation after 3 second. >> time.Sleep(3 * time.Second) >> log.Println("Canceling doWork goroutine reach 3s...") >> close(done) >> }() >> >> <-terminated //4 >> log.Println("Done.") >> } >> >> >> >> func goToSleep(){ >> >> >> >> >> rand.Seed(time.Now().UnixNano()) >> n := rand.Intn(12) // n will be between 0 and 10 >> log.Println("Sleeping ",n,"seconds..") >> time.Sleep(time.Duration(n)*time.Second) >> log.Println("Done sleeping!") >> } >> >> //------------------------------------------------ >> >> >> >> El lunes, 24 de febrero de 2020, 6:09:09 (UTC-3), Lutz Horn escribió: >>> >>> > I've tried to adapt from from "Concurrency in Go by Katherine >>> Cox-Buday" to >>> > understand how to apply timeout. But I don't get it. >>> >>> What are you trying to do? What is the expected behaviour, what happens >>> instead? >>> >>> BTW, this code does not compile, there are same unbalanced curly >>> brackets. >>> >>> Lutz >>> >> -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/b0828575-fddf-4024-bec0-8faf5b9858a4%40googlegroups.com.
