Ian,
continuation question -- does `type intElement list.Element(int)` introduce
a new type just like `type myInt int` does? If so, in a previous example,
these 2 maps are not of the same type, am I right?
Thank you very much,
Andrey
On Wednesday, July 1, 2020 at 10:50:07 AM UTC-6, Ian Lance Taylor wrote:
>
> On Wed, Jul 1, 2020 at 9:39 AM <aurelie...@gmail.com <javascript:>>
> wrote:
> >
> > Is this expected?
> >
> > import "list" // for 'std' list.go2
> >
> > func main() {
> > type intElement list.Element(int)
> > _ = make(map[int]intElement) // ok: compiles
> >
> > // nok
> > _ = make(map[int]list.Element(int)) // cannot use generic type
> list.Element(type TElem) without instantiation
> > }
> >
> > I don't think it is, but in case it is, how would I instantiate a
> make(map[int]intElement) without having to typedef a generic type before.
>
> From the parser's perspective the argument to make is an expression,
> so in this case you need parentheses to keep this from looking like a
> type conversion.
>
> make(map[int](list.Element(int)))
>
> Ian
>
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