Unless a channel is buffered, it is synchronous. A send cannot take place
until the reader is ready to receive.
You can make it buffered using
numCh = make(chan int, 1)
go write()
go read()
Or you can have two calls to read():
numCh = make(chan int)
go write()
go read()
go read()
On Wednesday, 27 July 2022 at 08:13:34 UTC+1 aravind...@gmail.com wrote:
> Hi All,
> When I was explaining basics of channels to newcomers, I was using the
> below example
> https://go.dev/play/p/xx2qqU2qqyp
>
> I was expecting both Write 5 and Write 3 to be printed. But only Write 5
> was printed. I couldn't reason out the behaviour, can somebody point out
> what I am assuming wrong about.
>
> Thanks,
> Aravindhan K
>
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to golang-nuts+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/golang-nuts/a831b7a2-95fe-4a65-ab75-7d361ce4d577n%40googlegroups.com.
