> This works in general, but your example is flawed.
oh, my bad, thanks for the clarification
> you'll receive a runtime panic instead of a compile error.
yeah, I've received the same feedback offline from one colleague some
minutes ago ... it is a bad idea
Thanks
On Wednesday, 31 August 2022 at 16:23:57 UTC+2 bse...@computer.org wrote:
> On Wed, Aug 31, 2022 at 7:28 AM antonio.o...@gmail.com <
> antonio.o...@gmail.com> wrote:
>
>> Hi,
>>
>> Based on the documentation:
>>
>> "The map key can be any type that is comparable."
>> "Struct values are comparable if all their fields are comparable. Two
>> struct values are equal if their corresponding non-blank fields are equal."
>> "Interface values are comparable. Two interface values are equal if they
>> have identical dynamic types and equal dynamic values or if both have value
>> nil."
>>
>> My understanding is that I can use an structure like this as a key for a
>> map
>>
>> type dialer interface {
>> dial()
>> }
>>
>> type key struct {
>> id string
>> number int
>> dialer dialer
>> }
>>
>> It also seems to work fine https://go.dev/play/p/hKQfx-JH5WP
>>
>
> This works in general, but your example is flawed. In your example, you
> have
>
> f1 := &fakedialer{}
> f2 := &fakedialer2{}
>
> and then use f1 anf f2 as keys. These are pointers to structs, so the
> comparison will be pointer comparison, not field-by-field comparison.
>
> If you do:
>
> f1 := fakedialer{}
> f2 := fakedialer2{}
>
> and replace the pointer receivers with value receivers, and then use these
> as map keys, it will work. But this time, if you pass a struct that cannot
> be used as a key, you'll receive a runtime panic instead of a compile error.
>
>
>> But I'm wondering if I'm missing something or are there some corner cases
>> I should take into account before doing this ... or if this is not
>> recommended at all
>>
>> Thanks,
>>
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