It does work (i.e., compiles) if you use a type alias (note the equal sign):
type uintXXX = uint
Whether it is a good idea to allow it to work using two distinct types that
have the same underlying type is debatable. Personally, I think the current
behavior (not allowing the conversion) is preferable.
On Sun, Jul 16, 2023 at 9:02 AM Leonard Mittmann <leonard.mittm...@gmail.com>
wrote:
> Hi everyone, I am wondering if there is efficient way to do the following
> type conversion (without looping over the map):
>
> var m = map[uint]uint{ /*...*/ }
> type uintXXX uint
> // this does not work
> var m2 map[uintXXX]uintXXX = (map[uintXXX]uintXXX)(m)
>
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>
--
Kurtis Rader
Caretaker of the exceptional canines Junior and Hank
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