Can you provide a link to your page, rather than just a code snippet? Jeremy R. Geerdes Effective website design & development Des Moines, IA
For more information or a project quote: http://jgeerdes.home.mchsi.com [EMAIL PROTECTED] Unless otherwise noted, any price quotes contained within this communication are given in US dollars. If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan Church! On Oct 21, 2008, at 6:02 AM, Kromitvs wrote: > > Hy, > I came across an error on my application. Here is a snippet of code. > You will notice I list in the begging several expressions witch also > produce the same error, and others (similar to my eyes) which don't. > I've been using the general Search, and the Blog search. The error > seems to apear only on the Blog search! > > I'm at a lost here! > Can someone help? Reproduced it? Tell me what I'm doing wrong? Fix it? > (congratulate me on finding my first BUG?) > > Thanks!!!!!!!!! > > > CODE: > > <?php > > /* > Error > $teste[0] = 'aos%2Cma'; > $teste[2] = '1os%2Cma'; > $teste[5] = 'aos%2C3a'; > $teste[6] = 'aos%2Ca3'; > $teste[3] = 'aos%2Cmm'; > $teste[4] = 'aos%2Caa'; > $teste[6] = 'dfg%2Cma'; > $teste[7] = 'sfd%2Cma'; > $teste[8] = 'asd%2Cma'; > $teste[6] = 'dfg%20ma'; > $teste[8] = 'asd%21ma'; > > No error > $teste[1] = 'aos%2Cm'; > $teste[2] = 'aos%2C'; > $teste[3] = 'aos'; > $teste[4] = 'ao'; > $teste[5] = 'a'; > $teste[6] = '123%2C23'; > $teste[7] = 'qwe%2Cqw'; > $teste[8] = 'ads%2Cfd'; > $teste[9] = 'a%20s%2C%20a'; > $teste[10] = 'a%22%22%2Cm%20'; > $teste[11] = '%20os%2C%20a'; > $teste[12] = 'a%20%20%2C%20a'; > $teste[13] = 'a-s%2C--'; > $teste[14] = 'aaa%2Caa'; > $teste[15] = '222%2C22'; > $teste[1] = 'ooo%2Cma'; > $teste[2] = 'sss%2Cma'; > */ > > $teste[0] = 'aos%2Caa'; > $teste[6] = 'dfg%20ma'; > $teste[7] = 'sfd%22ma'; > $teste[11] = 'asd%2Dma'; > > foreach ($teste as $temp) > { > $QueryUrlBlogSearch = 'http://ajax.googleapis.com/ajax/services/ > search/ > blogs?v=1.0&q=' . $temp; > print '<strong><br / ><br /> ' . $temp . '</strong> : '; > > //===Google Blog Search AJAX API > $ch2 = curl_init(); > curl_setopt($ch2, CURLOPT_URL, $QueryUrlBlogSearch); > curl_setopt($ch2, CURLOPT_RETURNTRANSFER, 1); > curl_setopt($ch2, CURLOPT_REFERER, ''); > $SearchResult2 = curl_exec($ch2); > curl_close($ch2); > $jsonBlog = json_decode($SearchResult2); > // now have some fun with the results... (ye... right!) > > if ($jsonBlog->{'responseStatus'} != 200) > > { > var_dump ($jsonBlog); > print '<br />$jsonBlog->{responseStatus} : ' . $jsonBlog- >> {'responseStatus'}; > //die; > } > > elseif (!count($jsonBlog->{'responseData'}->{'results'})) print '<div > style="color:blue">No result!! :-)</div>' ; > > else > { > foreach ($jsonBlog->{'responseData'}->{'results'} as &$cc2) > print '<div style="color:green"> content ' . $cc2->{'content'} . > '</div>'; > } > > }//end outer foreach > ?> > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/Google-AJAX-Search-API?hl=en -~----------~----~----~----~------~----~------~--~---
